Update README.md

README.md

@@ -5,60 +5,88 @@ language:
 - en
 widget:
 - example_title: Reasoning
-  text: |
+  text: >
     <|im_start|>system
-    You are Hyperion, an AI assistant developed by Sebastian Gabarain with a focus in reasoning, coding, science, and other general-purpose subjects. You are an AI assistant that follows instruction extremely well. Help as much as you can.
+
+    You are Hyperion, an AI assistant developed by Sebastian Gabarain with a
+    focus in reasoning, coding, science, and other general-purpose subjects. You
+    are an AI assistant that follows instruction extremely well. Help as much as
+    you can.
+
     <|im_end|>
+
     <|im_start|>user
-    In this task, you are given a description of an object and its surroundings. Your
-    task is to describe the motion of the object mentioned in the description using
-    differential equations. The answer should be a mathematical expression in t. Description:
-    A ball is thrown up at 30 ft/sec from 3 feet off the ground. Solve this step-by-step,
+
+    In this task, you are given a description of an object and its surroundings.
+    Your
+
+    task is to describe the motion of the object mentioned in the description
+    using
+
+    differential equations. The answer should be a mathematical expression in t.
+    Description:
+
+    A ball is thrown up at 30 ft/sec from 3 feet off the ground. Solve this
+    step-by-step,
+
     explaining each step in detail.
+
     <|im_end|>
+
     <|im_start|>assistant
-    
   output:
-    text: |
-      Hyperion here. The task requires you to describe the motion of a ball thrown up using differential equations. Here's the detailed explanation of how to solve it:
+    text: >
+      Hyperion here. The task requires you to describe the motion of a ball
+      thrown up using differential equations. Here's the detailed explanation of
+      how to solve it:
+
 
       1. Identify the given information:
          - Initial velocity (v0): 30 ft/sec
          - Initial height (y0): 3 feet off the ground
-      
-      2. Determine the acceleration due to gravity (g) at sea level, which is approximately -32.2 ft/s^2. Since we're dealing with a short distance and not very high altitudes, we can consider this value of g as constant.
-      
-      3. Use Newton's second law of motion to find the differential equation that describes the motion:
+
+      2. Determine the acceleration due to gravity (g) at sea level, which is
+      approximately -32.2 ft/s^2. Since we're dealing with a short distance and
+      not very high altitudes, we can consider this value of g as constant.
+
+
+      3. Use Newton's second law of motion to find the differential equation
+      that describes the motion:
          - The net force acting on the ball is the sum of gravity (mg) and air resistance (which we will neglect for simplicity). So, Fnet = mg.
          - Since acceleration equals force divided by mass, a = Fnet/m. In this case, m cancels out, so a = g.
          - The motion equation becomes: dv/dt = g = -32.2 ft/s^2 (since we're moving upwards). This is the first differential equation.
-      
-      4. Since we want to describe the ball's position (y) as well, we need another differential equation. We can use kinematics equations:
+
+      4. Since we want to describe the ball's position (y) as well, we need
+      another differential equation. We can use kinematics equations:
          - The velocity equation is v = v0 + at. Substitute the value of a from step 3:
            dv/dt = -32.2 ft/s^2. Rewriting it as an integral:
             ∫dv = -32.2 ft/s^2 * dt
          - Integrating with respect to time, we get v(t) = -16.1 t + C (constant of integration).
-      
+
       5. Now we have two equations, one for velocity and another for position:
          - dv/dt = -32.2 ft/s^2 (equation 1)
          - v(t) = -16.1 t + C (equation 2)
-      
-      6. We need to find the constant C using the initial conditions given in the problem. We know that initially, at time t=0, the ball's velocity is v0:
+
+      6. We need to find the constant C using the initial conditions given in
+      the problem. We know that initially, at time t=0, the ball's velocity is
+      v0:
          - Equation 2 becomes v0 = -16.1 * 0 + C, which simplifies to C = v0 = 30 ft/sec (initial velocity).
-      
+
       7. Now we have both equations with the constants filled in:
          - dv/dt = -32.2 ft/s^2 (equation 1)
          - v(t) = -16.1 t + 30 ft/sec (equation 2)
-      
+
       8. Finally, we need to find the ball's position (y) as a function of time:
          - Use the second kinematics equation y = y0 + v0*t + ½*a*t^2 (since acceleration is constant, it can be moved outside the integral).
          - Substitute the values for v0 and a:
            y(t) = 3 ft + (30 ft/sec) * t + (-½ * 32.2 ft/s^2) * t^2
-      
+
       That's it! The differential equation describing the motion of the ball is:
          - dv/dt = -32.2 ft/s^2 (equation 1)
          - v(t) = -16.1 t + 30 ft/sec (equation 2)
          - y(t) = 3 ft + (30 ft/sec) * t - (16.1 t^2) ft (equation 3)
+datasets:
+- Locutusque/hyperion-dpo-v1.0
 ---
 # Hyperion-3.0-Mistral-7B-DPO