class Solution:
    def wordBreak(self, s: str, wordDict: List[str]) -> bool:
        # This line initializes a list called dp with a length of len(s) + 1.Each element of dp is initially set to False.
        dp = [False]*(len(s)+1)
        # This line sets the last element of dp (at index len(s)) to True.
        dp[len(s)] = True
        # This line initiates a backward loop starting from the second-to-last index of the string s (len(s) - 1) down to index 0.The loop iterates through each character of the string s from right to left.
        for i in range(len(s)-1, -1, -1):
            # This line initiates a loop iterating through each word w in the wordDict list.wordDict seems to be a list containing words that are being checked against substrings of the string s.
            for w in wordDict:
                # This line checks if the substring of s from index i to i+len(w) (where w is the current word being iterated over in wordDict) is equal to w.Additionally, it ensures that the end index of the substring does not exceed the length of s to avoid out-of-bounds errors.
                if (i+len(w)) <= len(s) and s[i: (i+len(w))] == w:
                    # If the condition in the previous line is satisfied (i.e., if the substring matches the current word), it sets dp[i] to the value of dp[i+len(w)].This essentially propagates the True value backward in the dp list.
                    dp[i] = dp[i+len(w)]
                # This line checks if dp[i] is True. If it is, it breaks out of the loop.This is done to optimize the process. Once a substring is found to match a word in wordDict, there's no need to check further substrings starting from that index.
                if dp[i]:
                    break
        # Finally, this line returns the value at the first index of the dp list, which indicates whether it's possible to segment the string s into words from wordDict. If dp[0] is True, it means such segmentation is possible; otherwise, it's not possible.
        return dp[0]
