#!/usr/bin/env python3

#
# Copyright (C) 2008-2022 Advanced Micro Devices, Inc. All rights reserved.
#
# Redistribution and use in source and binary forms, with or without modification,
# are permitted provided that the following conditions are met:
# 1. Redistributions of source code must retain the above copyright notice,
#    this list of conditions and the following disclaimer.
# 2. Redistributions in binary form must reproduce the above copyright notice,
#    this list of conditions and the following disclaimer in the documentation
#    and/or other materials provided with the distribution.
# 3. Neither the name of the copyright holder nor the names of its contributors
#    may be used to endorse or promote products derived from this software without
#    specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND
# ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
# WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
# IN NO EVENT SHALL THE COPYRIGHT HOLDER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT,
# INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING,
# BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA,
# OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY,
# WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE)
# ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE
# POSSIBILITY OF SUCH DAMAGE.

import struct
import bigfloat
from bigfloat import precision as preci

# define double_to_hex (or float_to_hex)
def double_to_hex(f):
        return hex(struct.unpack('<Q', struct.pack('<d', f))[0])

def hex_to_double(h):
        return float(struct.unpack("<d",struct.pack("<Q",h))[0])

table_size = 1024

for i in range(0, table_size):
        idx = float(i)/table_size
        h1 = 0.0
        with preci(80):
                h1 = bigfloat.pow(2, idx)

        myhex = double_to_hex(h1)
        print("{ %s,"%myhex, end='')

        b = int(myhex, base=16) & ~( (1 << 26) - 1)
        print("\t0x%x,\t"%b, end='')

        d = h1 - hex_to_double(b)
        print("%s },"%double_to_hex(d))

        if i % 16 == 0:
                print()

